RPC stream client/server mutex fix (#884)
* Unlock RPC client while actually receiving a message As receiving a message might block for a long time, unblocking the client allows to let it send messages in the meanwhile without using 'tricks' * Unlock RPC server while actually receiving a message As receiving a message might block for a long time, unblocking the client allows to let it send messages in the meanwhile without using 'tricks' * Protect Close() against race conditions * Concurrency and Sequence tests
This commit is contained in:
committed by
Asim Aslam
parent
fa5b3ee9d9
commit
50b20413d3
@@ -83,7 +83,10 @@ func (r *rpcStream) Recv(msg interface{}) error {
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var resp codec.Message
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if err := r.codec.ReadHeader(&resp, codec.Response); err != nil {
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r.Unlock()
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err := r.codec.ReadHeader(&resp, codec.Response)
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r.Lock()
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if err != nil {
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if err == io.EOF && !r.isClosed() {
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r.err = io.ErrUnexpectedEOF
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return io.ErrUnexpectedEOF
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@@ -102,11 +105,17 @@ func (r *rpcStream) Recv(msg interface{}) error {
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} else {
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r.err = io.EOF
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}
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if err := r.codec.ReadBody(nil); err != nil {
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r.Unlock()
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err = r.codec.ReadBody(nil)
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r.Lock()
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if err != nil {
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r.err = err
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}
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default:
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if err := r.codec.ReadBody(msg); err != nil {
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r.Unlock()
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err = r.codec.ReadBody(msg)
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r.Lock()
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if err != nil {
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r.err = err
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}
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}
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@@ -121,11 +130,15 @@ func (r *rpcStream) Error() error {
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}
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func (r *rpcStream) Close() error {
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r.RLock()
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select {
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case <-r.closed:
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r.RUnlock()
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return nil
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default:
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close(r.closed)
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r.RUnlock()
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// send the end of stream message
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if r.sendEOS {
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